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CRYSTAL23
Latest v1.0.1
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Developer of the CRYSTAL code!

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  • geometry format error
    dmitoliundefined dmitoli

    Dear ywang,

    the issue is due to formatting: the number of atoms must be on a separate line, not at the end of the previous one. I have just checked this, and the input works correctly once formatted properly.

    Best,


  • geometry format error
    dmitoliundefined dmitoli

    Dear user,

    the error message reported in the output (i.e., "ERROR **** geometry **** FORMAT ERROR IN INPUT DECK") clearly indicates an issue in the input file. In particular, in the geometry block, after specifying the lattice parameters and before listing the fractional coordinates of the atoms, you must include the number of atoms in the primitive cell (which, in your case, is 6).

    Hope this helps.
    Best regards,


  • Question on HSE06 + SOC Support and MPI Abort in CRYSTAL23
    aerbaundefined aerba

    Let me just add that we do have a development version of the code for HSE+SOC, which we plan to include in the next release.


  • Question on HSE06 + SOC Support and MPI Abort in CRYSTAL23
    GiacomoAmbrogioundefined GiacomoAmbrogio

    Hi masoud37,
    Unfortunately, range separated hybrids (as HSE06) are not supported in two-components calculations (ie SOC), as stated at page 166 of the User manual.

    Please consider using a global hybrid instead, as PBE0 or any other "custom" percentage of exact exchange in any GGA functional using the keyword HYBRID (refer to page 135 of the manual).

    Hope this helps.


  • malloc during BOLTZTRA (Pproperties)
    aerbaundefined aerba

    Thanks!
    Could you share also the .d12 CRYSTAL input that generated the .f9 file?


  • How create band structure in P1 symmetry
    aerbaundefined aerba

    Hi,

    Let me just add that of course in P1 there are no special high-symmetry points to guide you in the definition of the path, so you need to be a little creative. For instance, you can start from Gamma (0 0 0) and go to the edge of the FBZ along the b1 reciprocal lattice (1/2 0 0), to then go to (1/2 1/2 0), then to (0 1/2 0) then back to Gamma (0 0 0) and then to the edge along the b3 reciprocal lattice (0 0 1/2). Or something else! 🙂


  • segmentation fault with double free or corruption during SCF
    GiacomoAmbrogioundefined GiacomoAmbrogio

    Hi andrejsc,
    There is no "hardcoded" switch in the TOLINTEG keyword, I suspect that the quote from the manual comes from the "old days", when a threshold of \( 10^{-20} \) was considered absurdly small. However, with advances in hardware and the increasingly complex structures we want to compute, such thresholds are sometimes necessary.

    A small note: don't warry about going past machine precision with these small numbers. All evaluations of integral thresholds in the code are performed at the logaritmic level (ie only on the exponent), so you should be fine even with a value of 1 million in TOLINTEG (though maybe not fine in terms of computation time)


  • D infinity h symmetry
    dmitoliundefined dmitoli

    If you fear that a reduced symmetry might influence the thermodynamic results, you can simply run the calculation without imposing any symmetry at all. For a 3-atom system like CO₂ the computational cost is so minimal that you can run both symmetry-free and \(D_{4h}\) calculations. Comparing the two results should give you an indication of whether the imposed symmetry has any impact on the quantities you are interested in.


  • D infinity h symmetry
    dmitoliundefined dmitoli

    Hi Jonas,

    CRYSTAL does not implement point groups with infinite-order rotations, so \(D_{\infty h}\) cannot be used directly. For linear molecules like CO₂, the practical approach is to approximate the symmetry using a finite-order rotation group.

    In this case, \(D_{4h}\) (i.e., 24) is a good option in CRYSTAL. It preserves the key degeneracies of linear molecules, including the doubly degenerate bending modes of CO₂. Using a lower-symmetry group like \(D_{2h}\) would artificially lift these degeneracies.


  • PDOS Projection for Individual Orbital Components
    GiacomoAmbrogioundefined GiacomoAmbrogio

    Hi Orion,
    Looking at your input, I think you want to plot the orbital projected electronic DOS (in CRYSTAL this is done with the DOSS keyword, PDOS in CRYSTAL normally refers to phonon DOS).

    To obtain separate px py pz projections, the correct approach is:
    set the first parameter of DOSS to 2 (because you want two separate projections).
    After the main DOSS line, you must then add one line per projection, specifying which atomic orbitals (AOs) belong to each projection.
    Each line has the form:

    n AOs    index_1    index_2    ...    index_n
    

    The AO indices correspond to the ones printed in the CRYSTAL output. To find them, search in the SCF output for "LOCAL ATOMIC FUNCTIONS BASIS SET", you will see a table with all the basis set, that will look like this:

    *******************************************************************************
       ATOM   X(AU)   Y(AU)   Z(AU)  N. TYPE  EXPONENT  S COEF   P COEF   D/F/G COEF
    *******************************************************************************
      1 O   -2.793  -4.838  -4.110
                                     1 S
                                            8.589E+03 1.895E-03 0.000E+00 0.000E+00
                                            1.297E+03 1.439E-02 0.000E+00 0.000E+00
                                            2.993E+02 7.073E-02 0.000E+00 0.000E+00
                                            8.738E+01 2.400E-01 0.000E+00 0.000E+00
                                            2.568E+01 5.948E-01 0.000E+00 0.000E+00
                                            3.740E+00 2.808E-01 0.000E+00 0.000E+00
                              2-     5 SP
                                            4.212E+01 1.139E-01 3.651E-02 0.000E+00
                                            9.628E+00 9.208E-01 2.372E-01 0.000E+00
                                            2.853E+00-3.274E-03 8.197E-01 0.000E+00
                              6-     9 SP
                                           9.057E-01 1.000E+00 1.000E+00 0.000E+00
                             10-    13 SP
                                            2.556E-01 1.000E+00 1.000E+00 0.000E+00
                             14-    18 D
                                            1.292E+00 0.000E+00 0.000E+00 1.000E+00
    

    The indeces are the numbers befor each orbital shell (1 2-5 6-9 10-13 14-18).
    The notation 2-5 means indices 2 through 5, because that shell contains 4 AOs.
    From these blocks you must identify the p-type orbitals for each atom (Zn and Cl). The p shells will appear in groups of three basis functions (px, py, pz).

    So, in your system:

    • Locate the Zn atom in this printed basis list
    • Identify the block corresponding to its p orbitals
    • Extract the AO indices for px, py, pz
    • Do the same for Cl

    Then you define one projection per line. For example, structurally something like:

    NEWK
    12 12
    1 0
    DOSS
    2 100 3 6 1 12 0
    3 <list of Zn p AOs>
    3 <list of Cl p AOs>
    END
    

    Keep in mind that, if your basis is double- or triple-Z, each p shell appears as a separate triplet of AOs (one triplet per Z). To correctly project all p you must include the corresponding AOs from every p-shell triplet for that atom.

    Let me know if you manage to do this, or if you need further help.

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CrystalSupportundefined CrystalSupport
ldonaundefined ldona
Chiaraundefined Chiara
Jacquesundefined Jacques
bcivalleriundefined bcivalleri
aerbaundefined aerba
SilviaCasassaundefined SilviaCasassa
dmitoliundefined dmitoli
GiacomoAmbrogioundefined GiacomoAmbrogio
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